40=x+(x^2/20)

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Solution for 40=x+(x^2/20) equation: 


x in (-oo:+oo)

40 = (x^2)/20+x // - (x^2)/20+x

40-((x^2)/20)-x = 0

40-1/20*x^2-x = 0

DELTA = (-1)^2-(-1/20*4*40)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(-1/20*2) or x = (1-9^(1/2))/(-1/20*2)

x = -40 or x = 20

x in { -40, 20 }

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